Question 9: The activation energy for the reaction 2HI

Question 9

The activation energy for the reaction 2HI(g) → H2 + I2(g) is 209.5 kJ mol-1 at 581 K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

Answer

In the given case:

Ea = 209.5 kJ mol – 1 = 209500 J mol – 1

T = 581 K

R = 8.314 JK – 1 mol – 1

Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as

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